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Find the remainder of the following case when f(x) is divided by g(x). f(x) = x2 + 6x + 10, g(x) = x − 3 - Mathematics

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Question

Find the remainder of the following case when f(x) is divided by g(x).

f(x) = x2 + 6x + 10, g(x) = x − 3

Sum
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Solution

Step 1: Convert g(x) to (x – a) form

x − 3 = 0

x = 3

Step 2: Calculate the remainder

f(3) = 32 + 6(3) + 10

= 9 + 18 + 10

= 37

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Chapter 6: Factorisation of polynomials - Exercise 6A [Page 104]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 6 Factorisation of polynomials
Exercise 6A | Q 1. (i) | Page 104
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