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Question
Find the remainder of the following case when f(x) is divided by g(x).
f(x) = x2 + 6x + 10, g(x) = x − 3
Sum
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Solution
Step 1: Convert g(x) to (x – a) form
x − 3 = 0
x = 3
Step 2: Calculate the remainder
f(3) = 32 + 6(3) + 10
= 9 + 18 + 10
= 37
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