Advertisements
Advertisements
Question
Find the perimeter of the adjoining figure, which is a semicircle including its diameter.

Advertisements
Solution
Radius = `10/5`
= 5 cm
Circumference of semicircle = `(2pi r)/2`
= `2 xx 1/2 xx 22/7 xx 5`
= 15.71 cm
Total perimeter = Circumference of semicircle + Length of diameter
= 15.71 + 10
= 25.71 cm
APPEARS IN
RELATED QUESTIONS
The length of a rectangular park is twice its breadth and its perimeter is 840 m. Find the area of the park.
The area of a rectangular plot is ` 462m^2` and is length is 28 m. Find its perimeter.
A rectangular park 358 m long and 18 m wide is to be covered with grass, leaving 2.5 m uncovered all around it. Find the area to be laid with grass.
The inside perimeter of a running track (shown in the following figure) is 400 m. The length of each of the straight portion is 90 m and the ends are semi-circles. If the track is everywhere 14 m wide. find the area of the track. Also find the length of the outer running track.

A wire is bent to form a square enclosing an area of 484 cm2. Using the same wire, a circle is formed. Find the area of the circle.
The length of the minute hand of a clock is 21 cm. The area swept by the minute hand in 10 minutes is
If a square in inscribed in a circle, find the ratio of the areas of the circle and the square.
A circular field of radius 105 m has a circular path of uniform width of 5 m along and inside its boundary. Find the area of the path.
The diameters of three wheels are in the ratio 2 : 4 : 8. If the sum of the circumferences of these circles be 132 cm, find the difference between the areas of the largest and the smallest of these wheels.
If the radius of a circle is tripled, the area becomes ______.
