Advertisements
Advertisements
Question
Lalitha wants to buy a round carpet of radius is 63 cm for her hall. Find the area that will be covered by the carpet
Advertisements
Solution
Radius of the round carpet = 63 cm
Area covered by the round carpet = πr2 sq.units
A = `22/7 xx 63 xx 63`
= 22 × 9 × 63
= 12474 cm2
Area covered by the round carpet = 12,474 cm2
APPEARS IN
RELATED QUESTIONS
A circular flower garden has an area of 314 m2. A sprinkler at the centre of the garden can cover an area that has a radius of 12 m. Will the sprinkler water the entire garden? (Take π = 3.14)
A carpet is laid on the floor of a room 8 m by 5 m. There is a border of constant width all around the carpet. If the area of the border is 12 m2, find its width.
The outer circumference of a circular race-track is 528 m . The track is everywhere 14 m wide. Calculate the cost of levelling the track at the rate of 50 paise per square metre.
`(use pi=22/7). `
A circle is inscribed in an equilateral triangle ABC is side 12 cm, touching its sides (the following figure). Find the radius of the inscribed circle and the area of the shaded part.

In the following figure, ABCD is a trapezium of area 24.5 cm2 , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region. [CBSE 2014]

If a square is inscribed in a circle, what is the ratio of the areas of the circle and the square?
The ratio of the outer and inner perimeters of a circular path is 23 : 22. If the path is 5 metres wide, the diameter of the inner circle is
The area of the incircle of an equilateral triangle of side 42 cm is
A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, π = 3.14) is ______.
If the perimeter of a semicircular protractor is 72 cm where `pi = 22/7`, then the diameter of protractor is ____________.
