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Question
Find the perimeter of a rectangle with length = 24 cm and diagonal = 25 cm
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Solution
Length of a rectangle (l) = 24 cm, Diagonal = 25 cm
Let breadth of the rectangle = b m
Applying Pythagoras Theorem in triangle ABC,
We get, (AC)2 = (AB)2 + (BC)2
(25)2 = (24)2 + (b)2
625 = 576 + (b)2
625 – 576 = b2
49 = b2
`sqrt(7xx7)` = b
∴ b = 7 cm
Now, perimeter of the rectangle
= 2(1 + b)
= 2(24 + 7)
= 2(31)
= 62 cm
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