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Question
Find the oxidation number of the element in the following compound.
Zn in ZnSO4
One Line Answer
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Solution
ZnSO4
1(Zn) + 1 (S) + 4 (0) = 0
x + 1(+6) + 4(-2) = 0
x + 6 – 8 = 0
x = + 2
Oxidation number of Zn in ZnSO4 is +2
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