Question

Find the oxidation number of the element in the following compound.

Zn in ZnSO₄

Answer 1

ZnSO₄
1(Zn) + 1 (S) + 4 (0) = 0
x + 1(+6) + 4(-2) = 0
x + 6 – 8 = 0
x = + 2
Oxidation number of Zn in ZnSO₄ is +2