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Question
Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.
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Solution
F = 20 N ⊥ distance = 0.5 m
Moment of force = Force x perpendicular distance of force from the point of rotation
= F x ⊥ distance
= 20 N × 0.5 m
= lONm
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