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Question
Find the mode for the following distribution.
| Ages (in years) | 1 – 10 | 11 – 20 | 21 – 30 | 31 – 40 | 41 – 50 |
| No. of children | 2 | 3 | 5 | 7 | 1 |
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Solution
1. Make class boundaries continuous
The original data is given in an discontinuous format (inclusive series). To analyze it accurately, we subtract 0.5 from each lower limit and add 0.5 to each upper limit:
| Age Interval (Inclusive) |
Continuous Class Boundaries |
No. of Children (f) |
| 1 – 10 | 0.5 – 10.5 | 2 |
| 11 – 20 | 10.5 – 20.5 | 3 |
| 21 – 30 | 20.5 – 30.5 | 5 |
| 31 – 40 | 30.5 – 40.5 | 7 (f1) |
| 41 – 50 | 40.5 – 50.5 | 1 |
2. Identify the modal class variables
The highest frequency is 7, which belongs to the continuous class interval 30.5 – 40.5.
Lower boundary of the modal class (L) = 30.5
Frequency of the modal class (f1) = 7
Frequency of the preceding class (f0) = 5
Frequency of the succeeding class (f2) = 1
Class width (h) = 40.5 – 30.5 = 10
3. Compute using the mode formula
Using the grouped data mode formula:
Mode = `L + ((f_1 - f_0)/(2f_1 - f_0 - f_2)) xx h`
Substitute the extracted values into the formula:
Mode = `30.5 + ((7 - 5)/(2(7) - 5 - 1)) xx 10`
Mode = `30.5 + (2/(14 - 6)) xx 10`
Mode = `30.5 + (2/8) xx 10`
Mode = 30.5 + 0.25 × 10
Mode = 30.5 + 2.5
Mode = 33.5
