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Find the mean of the following frequency distribution: Class 1 – 3 3 – 5 5 – 7 7 – 9 Frequency 9 22 27 18

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Question

Find the mean of the following frequency distribution: 

Class 1 – 3 3 – 5 5 – 7 7 – 9
Frequency 9 22 27 18
Sum
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Solution

1. Find the class marks

The class mark (xi) for each interval is calculated as the average of its lower and upper limits using the formula:

`x_i = ("Lower Limit" + "Upper Limit")/2`

For 1 – 3: `x_1 = (1 + 3)/2 = 2`

For 3 – 5: `x_2 = (3 + 5)/2 = 4`

For 5 – 7: `x_3 = (5 + 7)/2 = 6`

For 7 – 9: `x_4 = (7 + 9)/2 = 8`

2. Calculate the products and sums

Multiply each frequency (fi) by its corresponding class mark (xi), then find the total sum of the frequencies (Σfi) and the products (Σfixi).

Class Interval Frequency (fi) Class Mark (xi) fixi
1 – 3 9 2 18
3 – 5 22 4 88
5 – 7 27 6 162
7 – 9 18 8 144
Total Σfi = 76   Σfixi = 412

3. Apply the mean formula

The formula for the mean `(barx)` of grouped data is:

`barx = (sumf_ix_i)/(sumf_i)`

Substitute the calculated sums into the formula:

`barx = 412/76 ≈ 5.421`

The mean of the given frequency distribution is 5.42.

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Chapter 18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - TEST YOURSELF [Page 908]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 18 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
TEST YOURSELF | Q 9. | Page 908
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