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प्रश्न
Find the mean of the following frequency distribution:
| Class | 1 – 3 | 3 – 5 | 5 – 7 | 7 – 9 |
| Frequency | 9 | 22 | 27 | 18 |
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उत्तर
1. Find the class marks
The class mark (xi) for each interval is calculated as the average of its lower and upper limits using the formula:
`x_i = ("Lower Limit" + "Upper Limit")/2`
For 1 – 3: `x_1 = (1 + 3)/2 = 2`
For 3 – 5: `x_2 = (3 + 5)/2 = 4`
For 5 – 7: `x_3 = (5 + 7)/2 = 6`
For 7 – 9: `x_4 = (7 + 9)/2 = 8`
2. Calculate the products and sums
Multiply each frequency (fi) by its corresponding class mark (xi), then find the total sum of the frequencies (Σfi) and the products (Σfixi).
| Class Interval | Frequency (fi) | Class Mark (xi) | fixi |
| 1 – 3 | 9 | 2 | 18 |
| 3 – 5 | 22 | 4 | 88 |
| 5 – 7 | 27 | 6 | 162 |
| 7 – 9 | 18 | 8 | 144 |
| Total | Σfi = 76 | Σfixi = 412 |
3. Apply the mean formula
The formula for the mean `(barx)` of grouped data is:
`barx = (sumf_ix_i)/(sumf_i)`
Substitute the calculated sums into the formula:
`barx = 412/76 ≈ 5.421`
The mean of the given frequency distribution is 5.42.
