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Maharashtra State BoardSSC (English Medium) 10th Standard

Find the mean by step deviation method. Class 10 – 15 15 – 20 20 – 25 25 – 30 30 – 35 35 – 40 Frequency 5 6 8 12 6 3

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Question

Find the mean by step deviation method. 

Class 10 – 15 15 – 20 20 – 25 25 – 30 30 – 35 35 – 40
Frequency 5 6 8 12 6 3
Sum
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Solution

1. Formula

The formula for finding the mean using the step-deviation method is:

Mean `(barx) = A + ((sumf_iu_i)/(sumf_i)) xx h`

Where:

A = Assumed mean (middle value from class marks xi)

h = Class width (upper limit – lower limit = 15 – 10 = 5)

`u_i = (x_i - A)/h`

xi = Class mark (midpoint of each class) = `("Lower limit" + "Upper limit")/2`

2. Calculation table

The assumed mean A = 22.5 and class width h = 5:

Class Frequency
(fi)
Class Mark
(xi)
`bb(u_i = (x_i - 22.5)/5)` fiui
10 – 15 5 12.5 –2 –10
15 – 20 6 17.5 –1 –6
20 – 25 8 22.5 (A) 0 0
25 – 30 12 27.5 1 12
30 – 35 6 32.5 2 12
35 – 40 3 37.5 3 9
Total Σfi = 40     Σfiui = 40
 
3. Substitute values into the formula

Substituting the sums into the step deviation equation:

`barx = 22.5 + (17/40) xx 5`

`barx = 22.5 + 17/8`

`barx` = 22.5 + 2.125

`barx` = 24.625

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Chapter 6: Statistics - Q.4
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