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Question
Find the length of the longest rod that can be placed in a room of 12 ft. long, 9 ft broad and 8 ft. high.
Sum
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Solution
Given: Room dimensions: length = 12 ft, breadth = 9 ft, height = 8 ft.
Step-wise calculation:
1. The longest rod that can fit is the space diagonal of the rectangular box room.
2. Use 3D Pythagoras:
`d = sqrt(l^2 + b^2 + h^2)`
3. Substitute values:
`d = sqrt(12^2 + 9^2 + 8^2)`
= `sqrt(144 + 81 + 64)`
= `sqrt(289)`
= 17 ft
The length of the longest rod that can be placed in the room is 17 ft.
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