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Question
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = Product of the integers.
96 and 120
Sum
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Solution
Given: 96 and 120.
Step-wise calculation:
1. Prime factorisation:
96 = 25 × 3
120 = 23 × 3 × 5
2. HCF (product of common primes with smallest powers):
Common primes: 2 (min power 3) and 3 (min power 1)
HCF = 23 × 3
= 8 × 3
= 24
3. LCM (product of primes with largest powers):
Take 25, 31, 51
LCM = 25 × 3 × 5
= 32 × 3 × 5
= 480
4. Verify LCM × HCF = Product of the integers:
96 × 120 = 11,520
HCF × LCM = 24 × 480 = 11,520
Equality holds.
HCF = 24, LCM = 480 and LCM × HCF = 96 × 120 = 11,520 (verified).
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Chapter 1: Real Numbers - EXERCISE 1.4 [Page 1.30]
