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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the distance between the line 4x + 3y + 4 = 0, and a point (−2, 4) - Mathematics

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Question

Find the distance between the line 4x + 3y + 4 = 0, and a point (−2, 4)

Sum
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Solution

The distance between the line ax + by + c = 0 and the point (x1, y1) is d = `("a"x_1 + "b"y_1 + "c")/(sqrt("a"^2 + "b"^2)`

Here (x1, y1) = (−2, 4) and the equation of the line is 4x + 3y + 4 = 0

∴ Required dostance = `(4(- 2) + 3(4) + 4)/sqrt(4^2 + 3^2)`

= `(- 8 + 12 + 4)/(sqrt(16 + 9)`

= `8/5`

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Chapter 6: Two Dimensional Analytical Geometry - Exercise 6.3 [Page 271]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 6 Two Dimensional Analytical Geometry
Exercise 6.3 | Q 3. (i) | Page 271

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