Advertisements
Advertisements
Question
Find the distance between the following pair of points
(3, −9) and (−2, 3)
Advertisements
Solution
Distance between the two points (3, −9) and (−2, 3)
= `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
= `sqrt((-2 - 3)^2 + (3 + 9)^2`
= `sqrt((-5)^2 + (12)^2`
= `sqrt(25 + 144)`
= `sqrt(169)`
= 13 units
APPEARS IN
RELATED QUESTIONS
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 4, y = - 8
On a number line, the co-ordinates of P, Q, R are 3, -5 and 6 respectively. State with reason whether the following statement is true or false.
d(R, P) + d(P, Q) = d(R, Q)
Co-ordinates of the pair of a point is given below. Hence find the distance between the pair.
3, 6
If P-Q-R and d(P, Q) = 3.4, d(Q, R)= 5.7 then d(P, R) = ?
Co-ordinate of point A on a number line is 1. What are the co-ordinates of points on the number line which are at a distance of 7 units from A?
Determine whether the given set of points are collinear or not
(a, −2), (a, 3), (a, 0)
Show that the following points taken in order to form an isosceles triangle
A(6, −4), B(−2, −4), C(2, 10)
Verify that the following points taken in order to form the vertices of a rhombus
A(3, −2), B(7, 6), C(−1, 2) and D(−5, −6)
The abscissa of a point A is equal to its ordinate, and its distance from the point B(1, 3) is 10 units, What are the coordinates of A?
Find the distance with the help of the number line given below.

d(P, J)
