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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the derivatives of the following:xy = yx

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Question

Find the derivatives of the following:
xy = yx

Sum
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Solution

xy = yx

Taking log on both sides

log xy = log yx

y log x = x log y

Differentiate with respect to x

`y xx 1/x + (log x) ("d"y)/("d"x) = x * 1/y xx ("d"y)/("d"x) + (log y) 1`

`y/x + (log x) ("d"y)/("d"x) = x/y * ("d"y)/("d"x) + log y`

`(log ) ("d"y)/("d"x) - x/y ("d"y)/("d"x) = log y - y/x`

`(log x - x/y) ("d"y)/("d"x) = log y - y/x`

`(y log x - x)/y * ("d"y)/("d"x) = (x log y - y)/x`

`("d"y)/("d"x) = y/x * (x log y - y)/(y log x - x)`

`("d"y)/("d"x) = (y (x log y - y))/(x(y log x - x))`

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Chapter 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.4 [Page 176]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.4 | Q 4 | Page 176

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