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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Differentiate the following:y = sin3x + cos3x - Mathematics

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Question

Differentiate the following:
y = sin3x + cos3x

Sum
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Solution

y = sin3x + cos3x

Here u = sin3x = (sin x)3 

⇒ `("d"u)/("d"x)` = 3(sin x)2(cos x)

= 3sin2x cosx

v = cos3x = (cos x)

⇒ `("d"u)/("d"x)` = 3(cos x)2 (– sin x)

= – 3 sin x cos2x

Now y = u + v

⇒ `("d"y)/("d"x) = ("d"u)/("d"x) + ("d"v)/("d"x)`

= 3 sin2x cos x – 3sin x cos2x

= 3 sin x cos x (sin x – cos x)

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Differentiation Rules
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Chapter 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.3 [Page 164]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.3 | Q 22 | Page 164

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