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Question
Differentiate the following:
y = sin2(cos kx)
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Solution
y = sin2(cos kx)
y = f(g(x)
`("d"y)/("d"x)` = f'(g(x)) . g'(x)
`("d"y)/("d"x)` = 2 sin(cos kx) × cos(cos kx) × – sin kx × k × 1
`("d"y)/("d"x)` = sin(2 cos kx) × – k sin kx
`("d"y)/("d"x)` = – k sin kx . sin(2 cos kx)
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