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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the derivatives of the following functions with respect to corresponding independent variables: y = (x2 + 5) log(1 + x) e–3x

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Question

Find the derivatives of the following functions with respect to corresponding independent variables:

y = (x2 + 5) log(1 + x) e–3x 

Sum
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Solution

y = (x2 + 5) log(1 + x) e–3x 

`("d"y)/("d"x) = (x^2 + 5) [log (1 + x)"e"^(-3x) (- 3) + "e"^(-3x) xx 1/(1 + x)] + log(1 + x) * "e"^(-3x) (2x)`

`("d"y)/("d"x) = (x^2 + 5) [- 3"e"^(-3x) log(1 - x) + ("e"^(-3x))/(1 + x)] + 2x  "e"^(-3x) log(1 + x)`

`("d"y)/("d"x) = "e"^(-3x) [- 3(x^2 + 5) log(1 + x) + (x^2 + 5)/(1 + x)] + "e"^(-3x)  2x log(1 + x)`

`("d"y)/("d"x) = "e"^(- 3x) [- 3(x^2 + 5) log(1 + x) + (x^2 + 5)/(1 + x) + 2x log (1 + x)`

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Chapter 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.2 [Page 160]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.2 | Q 17 | Page 160

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