Question

Find the derivative of `y = log x + 1/x` with respect to x.

Answer 1

`y = log x + 1/x`

On differentiating both sides, w.r.t. x

`dy/dx = (d(logx))/dx + d/dx(1/x)`

= `1/x + ((-1)/x^2)`

= `1/x - 1/x^2`