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Find the derivative of x–4 (3 – 4x–5). - Mathematics

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Question

Find the derivative of x–4 (3 – 4x–5).

Sum
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Solution

Let f(x) = x–4 (3 – 4x–5)

By Leibnitz product rule,

f'(x) = `x^-4 d/(dx) (3 - 4x^-5) + (3 - 4x^-5) d/dx(x^-4)`

= x-4 {0 - 4 (-5) x-5-1} + (3 - 4x-5) (-4) x-4-1

= x-4 (20x-6) + (3 - 4x-5) (-4x-5)

= 20x-10 + 12x-5 + 16x-10

= 36x-10 - 12x-5

= `-12/x^5 + 36/x^10`

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Chapter 13: Limits and Derivatives - Exercise 13.2 [Page 313]

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NCERT Mathematics [English] Class 11
Chapter 13 Limits and Derivatives
Exercise 13.2 | Q 9.5 | Page 313

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