Advertisements
Advertisements
Question
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = 8y
Advertisements
Solution
x2 = 8y
x2 = 4(2)y
∴ a = 2
| Vertex | (0, 0) | (0, 0) |
| Focus | (0, a) | (0, 2) |
| Axis | y-axis | x = 0 |
| Directrix | y + a = 0 | y + 2 = 0 |
| Length of Latus rectum | 4a | 8 |
APPEARS IN
RELATED QUESTIONS
Find the vertex, focus, axis, directrix, and the length of the latus rectum of the parabola y2 – 8y – 8x + 24 = 0.
Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).
The eccentricity of the parabola is:
The distance between directrix and focus of a parabola y2 = 4ax is:
Find the equation of the parabola in the cases given below:
Vertex (1, – 2) and Focus (4, – 2)
Find the equation of the ellipse in the cases given below:
Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/25 - y^2/144` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 1)^2/100 + (y - 2)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
9x2 – y2 – 36x – 6y + 18 = 0
The latus-rectum of a conic section is:
