Advertisements
Advertisements
Question
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = - 16y
Advertisements
Solution
x2 = - 16y
x2 = - 4(4)y
∴ a = 4
| Vertex | (0, 0) | (0, 0) |
| Focus | (0, -a) | (0, -4) |
| Axis | y-axis | x = 0 |
| Directrix | y - a = 0 | y - 4 = 0 |
| Length of Latus rectum | 4a | 16 |
APPEARS IN
RELATED QUESTIONS
The focus of the parabola x2 = 16y is:
Find the equation of the parabola in the cases given below:
Focus (4, 0) and directrix x = – 4
Find the equation of the parabola in the cases given below:
Passes through (2, – 3) and symmetric about y-axis
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
x2 = 24y
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
x2 – 2x + 8y + 17 = 0
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/25 + y^2/9` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`y^2/16 - x^2/9` = 1
Show that the absolute value of difference of the focal distances of any point P on the hyperbola is the length of its transverse axis
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 3)^2/225 + (y - 4)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
9x2 – y2 – 36x – 6y + 18 = 0
