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Find the co-ordinates of point P which divides the line segment joining A(–2, –7) and B(6, 1) in the ratio 5 : 3.

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Question

Find the co-ordinates of point P which divides the line segment joining A(–2, –7) and B(6, 1) in the ratio 5 : 3.

Sum
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Solution

Here $$m : n = 5 : 3$$, $$A(x_1,y_1) = (-2, -7)$$ and $$B(x_2, y_2) = (6, 1)$$.

$$x=\frac{5 \times 6 + 3 \times (-2)}{5 + 3}$$

$$=\frac{30 - 6}{8}$$

$$=\frac{24}{8}$$

$$=3$$

$$y=\frac{5\times 1 + 3\times (-7)}{5 + 3}$$

$$=\frac{5 - 21}{8}$$

$$=\frac{-16}{8}$$

$$=-2$$

Hence the co-ordinates of P are $$P(3,-2)$$.

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Chapter 13: Section and Mid-point Formulae - EXERCISE 13 [Page 209]

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R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 13 Section and Mid-point Formulae
EXERCISE 13 | Q 1. (i) | Page 209
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