Advertisements
Advertisements
Question
Find the area of a rectangle whose length = 24 cm breadth =180 mm
Advertisements
Solution
length = 24 cm breadth =180 mm
⇒ length = 24 cm
breadth =180 mm = `180/10` cm = 18 cm
⇒ Area of the rectangle = Length × breadth
= 24 cm × 18 cm
= 432 cm2
APPEARS IN
RELATED QUESTIONS
In fig below, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8
cm and CF = 10 cm, find AD.
Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. Show that:
ar(ΔAPB) × ar(ΔCPD) = ar(ΔAPD) × ar (ΔBPC)
If AD is a median of a triangle ABC, then prove that triangles ADB and ADC are equal in
area. If G is the mid-point of median AD, prove that ar (Δ BGC) = 2 ar (Δ AGC).
In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).
If ABC and BDE are two equilateral triangles such that D is the mid-point of BC, then find ar (ΔABC) : ar (ΔBDE).
ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CQ: QP = 3.1. If ar (ΔPBQ) = 10cm2, find the area of parallelogram ABCD.
The sides of a rectangular park are in the ratio 4 : 3. If its area is 1728 m2, find
(i) its perimeter
(ii) cost of fencing it at the rate of ₹40 per meter.
Find the area of a square, whose side is: 4.5 cm.
If each square on this page is equal to 1 square meter of land, how much land will each of her children get? ________ square m
Each line gives a story. You have to choose the question which makes the best story problem. The first one is already marked.
- A shopkeeper has 50 boxes. There are 48 fruits in one box.
Tick the one question which matches with the given problem.
Explain why (a) and (c) are not good choices.a) How much will the shopkeeper pay in all? b) How many fruits are there in all? ✓ c) How many more boxes will he need?
