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Question
Find the angular momentum of an electron revolving in the second orbit in Bohr's hydrogen atom.
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Solution
The angular momentum of an electron revolving around the nucleus in a hydrogen atom is quantised and given by
`L = (nh)/(2pi)` For n = 2
`L = (2h)/(2pi) = h/pi = (6.6 xx 10^-34)/3.14`
= `2.10 xx 10^34` kg m2s-1
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