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Find the angle between the following two lines: λr→=2i^-5j^+k^+λ(3i^+2j^+6k^) μr→=7i^-6k^+μ(i^+2j^+2k^)

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Question

Find the angle between the following two lines:

`vecr = 2hati - 5hatj + hatk + λ(3hati + 2hatj + 6hatk)`

`vecr = 7hati - 6hatk + μ(hati + 2hatj + 2hatk)`

Sum
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Solution

Angle between two vectors

`vecr = veca_1 + λvecb_1` and `vecr = veca_2 + μvecb_2` is given by

cos θ = `|(vecb_1 . vecb_2)/(|vecb_1||vecb_2|)|`

`vecr = (2hati - 5hatj + hatk) + λ(3hati + 2hatj + 6hatk)`

`veca_1 = 2hati - 5hatj + hatk, vecb_1 = 3hati + 2hatj + 6hatk`

`vecr = (7hati - 6hatk) + μ(hati + 2hatj + 2hatk)`

`veca_2 = (7hati - 6hatk), vecb_2 = hati + 2hatj + 2hatk`

Now `vecb_1 . vecb_2 = (3hati + 2hatj + 6hatk) . (hati + 2hatj + 2hatk)`

= 3 + 4 + 12

= 19

`|vecb_1| = sqrt(3^2 + 2^2 + 6^2)`

= `sqrt(49)`

= 7

`|vecb_2| = sqrt(1^2 + 2^2 + 2^2)`

= `sqrt(9)`

= 3

cos θ = `|b_1 . b_2|/(|b_1||b_2|)`

cos θ = `|19/(7 xx 3)|`

= `19/21`

θ = `cos^-1  19/21`

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2022-2023 (March) Delhi Set 2

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