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Question
Find the 16th term from the end of the progression 3 + 6 + 9 + ... + 99.
Sum
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Solution
a = 3
d = 6 − 3
d = 3
Last term (l) = 99
an = l − (n − 1)d
= 99 − (16 − 1)3
= 99 − 45
= 54
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