Question

Find the 16th term from the end of the progression 3 + 6 + 9 + ... + 99.

Answer 1

a = 3

d = 6 − 3

d = 3

Last term (l) = 99

a_n = l − (n − 1)d

= 99 − (16 − 1)3

= 99 − 45

= 54