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प्रश्न
Which term of the progression `3/4 + 1 + 5/4 + ...` is 12?
योग
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उत्तर
a = `3/4`
d = `1 − 3/4 = 1/4`
d = `5/4 - 1 = 1/4`
d = `1/4`
an = 12
an = a + (n − 1)d
`12 = 3/4 + (n − 1)1/4`
Multiply the entire equation by 4 to clear the fractions:
48 = 3 + (n − 1)
48 = 3 + n − 1
48 = 2 + n
48 − 2 = n
n = 46
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