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Question
Find the number of degrees in each exterior exterior angle of a regular pentagon.
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Solution
\[\text{ Each exterior angle } = \left( \frac{360}{n} \right)^° \]
\[ \text{ For a regular pentagon, } n = 5 . \]
\[ \therefore\text{ Exterior angle } = \left( \frac{360}{5} \right)^° = 72° \]
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RELATED QUESTIONS
Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that.)
| Figure |  |
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| Side | 3 | 4 | 5 | 6 |
| Angle sum | 180° |
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3 × 180° = (5 − 2) × 180° |
4 × 180° = (6 − 2) × 180° |
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