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प्रश्न
Find the number of degrees in each exterior exterior angle of a regular pentagon.
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उत्तर
\[\text{ Each exterior angle } = \left( \frac{360}{n} \right)^° \]
\[ \text{ For a regular pentagon, } n = 5 . \]
\[ \therefore\text{ Exterior angle } = \left( \frac{360}{5} \right)^° = 72° \]
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संबंधित प्रश्न
Examine the table. (Each figure is divided into triangles and the sum of the angles deduced from that.)
| Figure |  |
 |
 |
 |
| Side | 3 | 4 | 5 | 6 |
| Angle sum | 180° |
2 × 180° = (4 − 2) × 180° |
3 × 180° = (5 − 2) × 180° |
4 × 180° = (6 − 2) × 180° |
What can you say about the angle sum of a convex polygon with number of sides?
a) 7
b) 8
c) 10
d) n
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Draw rough diagram to illustrate the following Open curve .
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The measure of each exterior angle of a regular pentagon is ______.
A regular polygon is a polygon whose all sides are equal and all ______ are equal.
If the sum of interior angles is double the sum of exterior angles taken in an order of a polygon, then it is a hexagon.
Find the measure of an are exterior angle of a regular pentagon and an exterior angle of a regular decagon. What is the ratio between these two angles?
A regular pentagon ABCDE and a square ABFG are formed on opposite sides of AB. Find ∠BCF.
