Question

Find the nature of roots of the following quadratic equations: 

`5x^2-4x+1=0`

Answer 1

The given equation is `5x^2-4x+1=0` 

This is of the form `ax^2+bx+c=0` where `a=3,b=-2sqrt6 and c=2` 

∴ Discriminant, `D=b^2-4ac=(-2sqrt6)^2-4xx3xx2=24-24=0`

Hence, the given equation has real and equal roots.