Question

Find the nature of roots of the following quadratic equations: 

` 3x^2-2sqrt6x+2=0` 

Answer 1

The given equation is `3x^2-2sqrt6x+2=0`  

This is of the form `ax^2+bx+c=0` where `a=2, b=-8 and c=5` 

∴ Discriminant, `D=b^2-4ac=(-2sqrt6)^2-4xx3xx2=24-24=0` 

Hence, the given equation has real and equal roots.