Question

`5x^2-4x+1=0` 

Answer 1

The given equation is 

`5x(x-2)+6=0` 

⇒`5x^2-10x+6=0` 

This is of the form `ax^2+bx+c=0` where `a=5, b=-10 and c=6` 

∴ Discriminant` D=b^2-4ac=(-10)^2-4xx5xx6=100-120=-20<0` 

Hence, the given equation has no real roots.