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Karnataka Board PUCPUC Science Class 11

Find the Magnetic Field B Due to a Semicircular Wire of Radius 10.0 Cm Carrying a Current of 5.0 a at Its Centre of Curvature.

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Question

Find the magnetic field B due to a semicircular wire of radius 10.0 cm carrying a current of 5.0 A at its centre of curvature.

Short/Brief Note
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Solution

Given:
Magnitude of current, I = 5 A
Radius of the semi-circular wire, r = 10 cm
∴ Required magnetic field at the centre of curvature 

\[B = \frac{1}{2} \times \frac{\mu_0 i}{2r}\]
\[ = {10}^{- 7} \times \frac{5}{10 \times {10}^{- 2}}\]
\[ = 5\pi \times {10}^{- 6} \]
\[ = 1 . 6 \times {10}^{- 5} \] T

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Chapter 35: Magnetic Field due to a Current - Exercises [Page 252]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 35 Magnetic Field due to a Current
Exercises | Q 41 | Page 252
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