Advertisements
Advertisements
Question
At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60°. What is the value of horizontal component of the earth's magnetic field at equator?
Advertisements
Solution
The horizontal component of the electric field is given by
BH=Becos(θ)
where θ is the angle of dip at the given place
Be is the net magnetic field
At θ=60°
BH=Becos(60)=Be×1/2
Be=2BH=2B (given BH=B)
Now horizontal component at equator
BH=Becos(θ)
angle of dip at equator is 0°
BH=Becos(0)=Be=2B
BH=2B
APPEARS IN
RELATED QUESTIONS
Use Biot-Savart law to derive the expression for the magnetic field on the axis of a current carrying circular loop of radius R.
Draw the magnetic field lines due to a circular wire carrying current I.
Using Biot-Savart law, deduce the expression for the magnetic field at a point (x) on the axis of a circular current carrying loop of radius R. How is the direction of the magnetic field determined at this point?
Derive the expression for the torque on a rectangular current carrying loop suspended in a uniform magnetic field.
Figure shows a long wire bent at the middle to form a right angle. Show that the magnitudes of the magnetic fields at the point P, Q, R and S are equal and find this magnitude.
A circular loop of radius r carries a current i. How should a long, straight wire carrying a current 4i be placed in the plane of the circle so that the magnetic field at the centre becomes zero?
A circular coil of 200 turns has a radius of 10 cm and carries a current of 2.0 A. (a) Find the magnitude of the magnetic field \[\vec{B}\] at the centre of the coil. (b) At what distance from the centre along the axis of the coil will the field B drop to half its value at the centre?
A charge of 3.14 × 10−6 C is distributed uniformly over a circular ring of radius 20.0 cm. The ring rotates about its axis with an angular velocity of 60.0 rad s−1. Find the ratio of the electric field to the magnetic field at a point on the axis at a distance of 5.00 cm from the centre.
If we double the radius of a coil keeping the current through it unchanged, then the magnetic field at any point at a large distance from the centre becomes approximately.
If ar and at represent radial and tangential accelerations, the motion of the particle will be uniformly circular, if:
