Question

Find graphical solution for the following system of linear in equation:

3x + 4y ≤ 12, x - 2y ≥ 2, y ≥ - 1

Answer 1

First we draw the lines AB, CD and ED whose equations are 3x + 4y = 12, x - 2y = 2 and y = - 1 respectively.

Line	Equation	Points on the X-axis	Points on the Y-axis	Sign	Region
AB	3x + 4y = 12	A(4, 0)	B(0, 3)	≤	origin side of line AB
CD	x - 2y = 2	C(2, 0)	D(0, -1)	≥	non-origin side of line CD
ED	y = - 1	-	D(0, -1)	≥	origin side of line ED

The solution set of given system of inequation is shaded in the graph.