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प्रश्न
Find graphical solution for the following system of linear in equation:
3x + 4y ≤ 12, x - 2y ≥ 2, y ≥ - 1
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उत्तर
First we draw the lines AB, CD and ED whose equations are 3x + 4y = 12, x - 2y = 2 and y = - 1 respectively.
| Line | Equation | Points on the X-axis | Points on the Y-axis | Sign | Region |
| AB | 3x + 4y = 12 | A(4, 0) | B(0, 3) | ≤ | origin side of line AB |
| CD | x - 2y = 2 | C(2, 0) | D(0, -1) | ≥ | non-origin side of line CD |
| ED | y = - 1 | - | D(0, -1) | ≥ | origin side of line ED |
The solution set of given system of inequation is shaded in the graph.
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