Advertisements
Advertisements
Question
Find the following squares by suing the identities
(xy + 3z)2
Advertisements
Solution
(xy + 3z)2 = (xy)2 + 2(xy) (3z) + (3z)2 [(a + b)2 = a2 + 2ab + b2]
= x2y2 + 6xyz + 9z2
APPEARS IN
RELATED QUESTIONS
Using a2 − b2 = (a + b) (a − b), find 512 − 492
Use a formula to multiply of (2t – 5)(2t + 5)
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 4x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x3 + 2abx2 + b2x
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
The area of a square is 9x2 + 24xy + 16y2. Find the side of the square.
The area of a circle is given by the expression πx2 + 6πx + 9π. Find the radius of the circle.
The height of a triangle is x4 + y4 and its base is 14xy. Find the area of the triangle.
Verify the following:
(a + b)(a + b)(a + b) = a3 + 3a2b + 3ab2 + b3
Verify the following:
(5x + 8)2 – 160x = (5x – 8)2
