Advertisements
Advertisements
प्रश्न
Find the following squares by suing the identities
(xy + 3z)2
Advertisements
उत्तर
(xy + 3z)2 = (xy)2 + 2(xy) (3z) + (3z)2 [(a + b)2 = a2 + 2ab + b2]
= x2y2 + 6xyz + 9z2
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
संबंधित प्रश्न
Use a suitable identity to get the following products.
(6x − 7) (6x + 7)
Using a2 − b2 = (a + b) (a − b), find (1.02)2 − (0.98)2
Use an expansion formula to find the value.
(1005)2
Evaluate the following, using suitable identity
1032
(a + b)2 – 2ab = ______ + ______.
The difference of the squares of two consecutive numbers is their sum.
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
x2 + 12x + 36
Factorise the following.
18 + 11x + x2
Verify the following:
(a + b)(a + b)(a + b) = a3 + 3a2b + 3ab2 + b3
Factorise p4 + q4 + p2q2.
