Advertisements
Advertisements
Question
Find the cube of 2.1 .
Sum
Advertisements
Solution
We have:
\[2 . 1 = \frac{21}{10}\]
Also,
\[\left( \frac{m}{n} \right)^3 = \frac{m^3}{n^3}\]
∴ \[\left( \frac{21}{10} \right)^3 = \frac{{21}^3}{{10}^3} = \frac{21 \times 21 \times 21}{10 \times 10 \times 10} = \frac{9261}{1000} = 9 . 261\]
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
There is no perfect cube which ends with 8.
Find the cube of −11 .
Find the cube of \[\frac{7}{9}\] .
Find the cube of 0.08 .
Evaluate : \[\sqrt[3]{4^3 \times 6^3}\]
Evaluate of the following
\[\sqrt[3]{27} + \sqrt[3]{0 . 008} + \sqrt[3]{0 . 064}\]
If `root(3)(729)` = 9 then `root(3)(0.000729) = ?`
Find the cube of 1.6.
Find the cube of: -12
There are ______ perfect cubes between 1 and 1000.
