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प्रश्न
Find the cube of 2.1 .
बेरीज
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उत्तर
We have:
\[2 . 1 = \frac{21}{10}\]
Also,
\[\left( \frac{m}{n} \right)^3 = \frac{m^3}{n^3}\]
∴ \[\left( \frac{21}{10} \right)^3 = \frac{{21}^3}{{10}^3} = \frac{21 \times 21 \times 21}{10 \times 10 \times 10} = \frac{9261}{1000} = 9 . 261\]
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