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Question
Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm,
DN = 3 cm, and
BM⊥AC, DN⊥AC
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Solution
ar (ABCD) = ar (ABC) + ar (ADC)
= `1/2` (3 × 22) + `1/2` (3 × 22)
= 33 + 33 = 66 cm2
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