Advertisements
Advertisements
Question
Find a rational number exactly halfway between:
`5/(-13)` and `(-7)/9`
Advertisements
Solution
We know that, a rational number, which is halfway between two rational number i.e. a and b = `(a + b)/2`
Given rational numbers are `5/(-13)` and `(-7)/9`
Here, a = `-5/13` and b = `-7/9`
∴ `(a + b)/2 = ((-5)/13 + (-7/9))/2`
= `((-5)/13 - 7/9)/2`
= `((-5 xx 9)/(13 xx 9) - (7 xx 13)/(9 xx 13))/2`
= `((-45)/177 - 91/177)/2`
= `((-45 - 91)/177)/2`
= `(-136)/(117 xx 2)`
= `(-136)/234`
Hence, the exactly of halfway between `5/(-13)` and `(-7)/9` is `-136/234`.
APPEARS IN
RELATED QUESTIONS
Represent these numbers on the number line
`7/4`
Show the following numbers on a number line. Draw a separate number line for the example.
`7/5 , (-2)/5 , (-4)/5`
Show the following numbers on a number line. Draw a separate number line for the example.
`13/10 , (-17)/10`
Show the number √5 on the number line.
Evaluate:
`5/9 + (-7)/6`
Evaluate:
`(-8)/9 + -5/12`
The rational number `(-8)/(-3)` lies neither to the right nor to the left of zero on the number line.
Write the following rational numbers in the descending order.
`8/7, (-9)/8, (-3)/2, 0, 2/5`
On a number line, `(-1)/2` is to the ______ of zero (0).
On a number line, `4/3` is to the ______ of zero (0).
