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प्रश्न
Find a rational number exactly halfway between:
`5/(-13)` and `(-7)/9`
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उत्तर
We know that, a rational number, which is halfway between two rational number i.e. a and b = `(a + b)/2`
Given rational numbers are `5/(-13)` and `(-7)/9`
Here, a = `-5/13` and b = `-7/9`
∴ `(a + b)/2 = ((-5)/13 + (-7/9))/2`
= `((-5)/13 - 7/9)/2`
= `((-5 xx 9)/(13 xx 9) - (7 xx 13)/(9 xx 13))/2`
= `((-45)/177 - 91/177)/2`
= `((-45 - 91)/177)/2`
= `(-136)/(117 xx 2)`
= `(-136)/234`
Hence, the exactly of halfway between `5/(-13)` and `(-7)/9` is `-136/234`.
APPEARS IN
संबंधित प्रश्न
Represent these numbers on the number line
`7/4`
The number `sqrt2` is shown on a number line. Steps are given to show `sqrt3` on the number line using `sqrt2`. Fill in the boxes properly and complete the activity.
Activity :
- The point Q on the number line shows the number ______.
- A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
- Right angled ∆ORQ is obtained by drawing seg OR.
`l ("OQ") = sqrt2` , `l("QR") = 1`
`therefore` by Pythagoras theorem,
`[l("OR")]^2 = [l("OQ")]^2 + [l("QR")]^2 `
= `square^2`+ `square^2` = `square` + `square`
= `square`
∴ l(OR) = `square`
Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number `sqrt3`.
Show the number √5 on the number line.
Show the following numbers on a number line.
`7/3, 2, (-2)/3`
Find the rational numbers represented by the question marks marked on the following number line
Draw a number line and represent the following rational numbers on it
`15/(-4)`
Arrange the numbers `1/4, 13/16, 5/8` in the descending order.
The rational number `(-3)/4` lies to the right of zero on the number line.
Find a rational number exactly halfway between:
`(-1)/3` and `1/3`
Find a rational number exactly halfway between:
`1/15` and `1/12`
