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Question
Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is t1 and from C to O is t2. The time period of this simple pendulum is
Options
(t1 + t2)
2(t1 + t2)
3(t1 + t2)
4(t1 + t2)
MCQ
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Solution
4(t1 + t2)
Explanation:
Time taken by the bob to move from
A to O = t1 + t2 = tAO = tOA
Similarly, tOB = t1 + t2 = tBO
So, time period = tAO + tOB + tBO + tOA = 4(t1 + t2)
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