Question

Figure shows an oscillating pendulum.

Time taken by the bob to move from A to C is t₁ and from C to O is t₂. The time period of this simple pendulum is

विकल्प

• (t₁ + t₂)

• 2(t₁ + t₂)

• 3(t₁ + t₂)

• 4(t₁ + t₂)

Answer 1

4(t₁ + t₂)

Explanation:

Time taken by the bob to move from

A to O = t₁ + t₂ = t_AO = t_OA

Similarly, t_OB = t₁ + t₂ = t_BO

So, time period = t_AO + t_OB + t_BO + t_OA = 4(t₁ + t₂)