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Question
Factorize the following expressions:
32a3 + 108b3
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Solution
32a3 +108b3
= 4(8a3 + 27b3)
= 4((2a)3 + (3b)3) [Using a3 + b3 = (a + b)(a2 - ab + b2)]
= 4 [(2a + 3b)((2a)2 - 2a x 3b + (3b)2)]
= 4(2a + 3b)(4a2 - 6ab + 9b2)
∴ 32a3 +108b3 = 4(2a + 3b)(4a2 - 6ab + 9b2 )
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