Advertisements
Advertisements
प्रश्न
Factorize the following expressions:
32a3 + 108b3
Advertisements
उत्तर
32a3 +108b3
= 4(8a3 + 27b3)
= 4((2a)3 + (3b)3) [Using a3 + b3 = (a + b)(a2 - ab + b2)]
= 4 [(2a + 3b)((2a)2 - 2a x 3b + (3b)2)]
= 4(2a + 3b)(4a2 - 6ab + 9b2)
∴ 32a3 +108b3 = 4(2a + 3b)(4a2 - 6ab + 9b2 )
APPEARS IN
संबंधित प्रश्न
Get the algebraic expression in the following case using variables, constants and arithmetic operations.
The number z multiplied by itself.
Factorize the following expressions
64a3 – b3
If 3x + 5y = 11 and xy = 2, find the value of 9x2 + 25y2
Write the value of 253 − 753 + 503.
Factorize : x2 − 1 − 2a − a2
Multiply: (-2x + 3y)(2x - 3y)
Divide: 6x2 - xy - 35y2 by 2x - 5y
Write in the form of an algebraic expression:
Perimeter (P) of a square is four times its side.
The rate of planting the grass is ₹ x per square metre. Find the cost of planting the grass on a triangular lawn whose base is y metres and height is z metres.
Shashi used addition to solve a word problem about the weekly cost of commuting by toll tax for ₹ 15 each day. Ravi solved the same problem by multiplying. They both got the correct answer. How is this possible?
