Advertisements
Advertisements
प्रश्न
Factorize the following expressions:
32a3 + 108b3
Advertisements
उत्तर
32a3 +108b3
= 4(8a3 + 27b3)
= 4((2a)3 + (3b)3) [Using a3 + b3 = (a + b)(a2 - ab + b2)]
= 4 [(2a + 3b)((2a)2 - 2a x 3b + (3b)2)]
= 4(2a + 3b)(4a2 - 6ab + 9b2)
∴ 32a3 +108b3 = 4(2a + 3b)(4a2 - 6ab + 9b2 )
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorize (x + 2)(x2 + 25) -10x2 - 20x
Factorize `x^2 + 5sqrt5x + 30`
Factorize the following expressions:
(a + b)3 – 8(a – b)3
Factorize the following expressions:
a12 + b12
Factorize the following expressions:
`a^3 - 1/a^3 - 2a + 2/a`
If x2 + y2 = 29 and xy = 2, find the value of x + y.
If x3 − 3x2 + 3x − 7 = (x + 1) (ax2 + bx + c), then a + b + c =
Divide: 8x + 24 by 4
Divide: 35a3 + 3a2b - 2ab2 by 5a - b
Divide: 6x2 - xy - 35y2 by 2x - 5y
